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A water trough of semicircular cross section of radius 0.7
Chapter 3, Problem 72P(choose chapter or problem)
Problem 72P
A water trough of semicircular cross section of radius 0.7 m consists of two symmetric parts hinged to each other at the bottom, as shown in Fig. P3–77. The two parts are held together by a cable and turnbuckle placed every 3 m along the length of the trough. Calculate the tension in each cable when the trough is filled to the rim.
Questions & Answers
QUESTION:
Problem 72P
A water trough of semicircular cross section of radius 0.7 m consists of two symmetric parts hinged to each other at the bottom, as shown in Fig. P3–77. The two parts are held together by a cable and turnbuckle placed every 3 m along the length of the trough. Calculate the tension in each cable when the trough is filled to the rim.
ANSWER:
Step 1
The tension of the cable will be equal to the horizontal force acting on the one half of the system by the other half. The horizontal force will come from the pressure of the water from the other half of the trough.
First calculate the pressure and then calculate the area of the where the pressure is acting. Then, by knowing the pressure and area for 3 m length of the trough, the force can be calculated. This horizontal force will be equal to the tension of the one of the cable.