Show that the function f(x) = ax + b from R to R is

Chapter 1, Problem 39E

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QUESTION:

Show that the function \(f(x)=a x+b\) from R to R is invertible. where a and b are constants, with \(a \neq 0\). and find the inverse of f.

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QUESTION:

Show that the function \(f(x)=a x+b\) from R to R is invertible. where a and b are constants, with \(a \neq 0\). and find the inverse of f.

ANSWER:

SolutionStep 1In the problem we have to prove function f(x) = ax + b from R to R invertible and Also find inverse.Let us assume that the function is defined that f(x) = ax + b = yWe have to Consider that f(x) is one to one function then Then, y = ax + bSubtracting b on both the sides we get, y - b = ax + b - b y - b = axNow Divide by a on both the sides we get, = xSo, for inverse switch x and y = yThis leads to a function p such that R to R can be p(x) =

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