A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant, its acceleration is 1.05 m/s2, in a direction that makes an angle of 32.0° to its direction of motion. Determine its speed (a) at this moment, and (b) 2.00 s later, assuming constant tangential acceleration.

Solution 27P

Step 1 of 3:

In this question, we need to find the speed of the speed

In part b, we need to find the speed after 2.00 s assuming particle has constant tangential acceleration

Data given

Radius of the circle

Acceleration of the particle

Angle made by the particle

Part a:

Step 2 of 3:

We need to find the speed of the speed

It is obtained using relation

Rearranging to find velocity

Substituting values we get

Hence we have speed of the particle as

Part b: