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# Answer: A particle revolves in a horizontal circle of ISBN: 9780321569837 99

## Solution for problem 27P Chapter 5

Physics: Principles with Applications | 6th Edition

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Problem 27P

A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant, its acceleration is 1.05 m/s2, in a direction that makes an angle of 32.0° to its direction of motion. Determine its speed (a) at this moment, and (b) 2.00 s later, assuming constant tangential acceleration.

Step-by-Step Solution:

Solution 27P

Step 1 of 3:

In this question, we need to find the speed of the speed

In part b, we need to find the speed after 2.00 s assuming particle has constant tangential acceleration

Data given

Radius of the circle Acceleration of the particle Angle made by the particle Part a:

Step 2 of 3:

We need to find the speed of the speed

It is obtained using relation  Rearranging to find velocity Substituting values we get  Hence we have speed of the particle as Part b:

Step 3 of 3

##### ISBN: 9780321569837

The answer to “A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant, its acceleration is 1.05 m/s2, in a direction that makes an angle of 32.0° to its direction of motion. Determine its speed (a) at this moment, and (b) 2.00 s later, assuming constant tangential acceleration.” is broken down into a number of easy to follow steps, and 50 words. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. Physics: Principles with Applications was written by and is associated to the ISBN: 9780321569837. Since the solution to 27P from 5 chapter was answered, more than 284 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 27P from chapter: 5 was answered by , our top Physics solution expert on 09/09/17, 04:43AM. This full solution covers the following key subjects: its, acceleration, direction, later, constant. This expansive textbook survival guide covers 33 chapters, and 4141 solutions.

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