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A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant
Chapter 5, Problem 27P(choose chapter or problem)
Problem 27P
A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant, its acceleration is 1.05 m/s2, in a direction that makes an angle of 32.0° to its direction of motion. Determine its speed (a) at this moment, and (b) 2.00 s later, assuming constant tangential acceleration.
Questions & Answers
QUESTION:
Problem 27P
A particle revolves in a horizontal circle of radius 2.90 m. At a particular instant, its acceleration is 1.05 m/s2, in a direction that makes an angle of 32.0° to its direction of motion. Determine its speed (a) at this moment, and (b) 2.00 s later, assuming constant tangential acceleration.
ANSWER:
Solution 27P
Step 1 of 3:
In this question, we need to find the speed of the speed
In part b, we need to find the speed after 2.00 s assuming particle has constant tangential acceleration
Data given
Radius of the circle
Acceleration of the particle
Angle made by the particle
Part a: