Option 3 : 240

**Given:**

The word has two vowels "i" and "o"

vowels should be arranged at two ends

**Formula used:**

^{n}p_{r = }n!/(n - r)!

**Calculation:**

possible ways of vowels are arranged at one ends is ^{2}p_{1 }(we have two vowels "I" or "o")

possible way of the vowel is arranged at another end is ^{1}p_{1} (only one vowel left)

now we have five remaining places so we can arrange four remaining letters to five remaining places by 4! ways

number of possible ways = 2p1 × 5! × ^{1}p1 (^{n}p_{n }= 1)

⇒ 2 × 5 × 4 × 3 × 2 × 1

⇒ 240

∴ **T****here are 240 possible arrangements.**

ME Subject Test 1: Strength of Materials

9318

20 Questions
20 Marks
18 Mins