Show that where is a sequence of real numbers. This type
Chapter 1, Problem 35E(choose chapter or problem)
Show that \(\sum_{j=1}^{n}\left(a_{j}-a_{j-1}\right)=a_{n}-a_{0}\), where \(a_{0}, a_{1}, \ldots, a_{n}\) is a sequence of real numbers. This type of sum is called telescoping.
Equation Transcription:
Text Transcription:
sum_ j=1^n(a_j − a_j-1) = a_n − a_0
a_0
a_1
a_n
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