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# Show that if |A| = |B| and |B| = |C|, then |A| = |C|. ISBN: 9780073383095 37

## Solution for problem 20E Chapter 2.5

Discrete Mathematics and Its Applications | 7th Edition

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Problem 20E

Show that if |A| = |B| and |B| = |C|, then |A| = |C|.

Step-by-Step Solution:

Solution:Step 1:In this question we have to prove that if |A| = |B| and |B| = |C|, then |A| = |C|.Step 2:According to Schroder-Bernstein Theorem states that if A and B are sets with |A| |B| and |B| |A|, then |A| = |C|. In other words, if there are one-to-one functions f from A to B and g from B to A, then there is a one-to-one correspondence between A and B.Step 3:Give us a chance to think about sets A, B and C to such an extent that aLikewise |A| = |B| and |B| = |C|a with the end goal that |A| = |B| and |B| = |C| Since, |A| = |B| there leave f: Abijection. Likewise, |B| = |C| there leave g: Bbijection.

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##### ISBN: 9780073383095

The full step-by-step solution to problem: 20E from chapter: 2.5 was answered by , our top Math solution expert on 06/21/17, 07:45AM. Since the solution to 20E from 2.5 chapter was answered, more than 240 students have viewed the full step-by-step answer. Discrete Mathematics and Its Applications was written by and is associated to the ISBN: 9780073383095. This full solution covers the following key subjects: show. This expansive textbook survival guide covers 101 chapters, and 4221 solutions. The answer to “Show that if |A| = |B| and |B| = |C|, then |A| = |C|.” is broken down into a number of easy to follow steps, and 14 words. This textbook survival guide was created for the textbook: Discrete Mathematics and Its Applications, edition: 7.

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