Show that if |A| = |B| and |B| = |C|, then |A| = |C|.

Solution:Step 1:In this question we have to prove that if |A| = |B| and |B| = |C|, then |A| = |C|.Step 2:According to Schroder-Bernstein Theorem states that if A and B are sets with |A| |B| and |B| |A|, then |A| = |C|. In other words, if there are one-to-one functions f from A to B and g from B to A, then there is a one-to-one correspondence between A and B.Step 3:Give us a chance to think about sets A, B and C to such an extent that aLikewise |A| = |B| and |B| = |C|a with the end goal that |A| = |B| and |B| = |C| Since, |A| = |B| there leave f: Abijection. Likewise, |B| = |C| there leave g: Bbijection.