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An unmarked police car, traveling a constant 95 km/h, is passed by a speeder traveling
Chapter 3, Problem 50P(choose chapter or problem)
An unmarked police car, traveling a constant 95 km/h, is passed by a speeder traveling 145 km/h. Precisely 1.00 s after the speeder passes, the policeman steps on the accelerator. If the police car’s acceleration is \(2.00 \mathrm{~m} / \mathrm{s}^{2}\), how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at constant speed)?
Questions & Answers
QUESTION:
An unmarked police car, traveling a constant 95 km/h, is passed by a speeder traveling 145 km/h. Precisely 1.00 s after the speeder passes, the policeman steps on the accelerator. If the police car’s acceleration is \(2.00 \mathrm{~m} / \mathrm{s}^{2}\), how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at constant speed)?
ANSWER:Step 1 of 4
Before the speeder passes the police car,
\({v_p} = 95\;\frac{{{\rm{km}}}}{{\rm{h}}}\)
\({v_s} = 145\;\frac{{{\rm{km}}}}{{\rm{h}}}\)
After \(1\;{\rm{second}}\) that, the speeder passes the police car,
\({a_p} = 2.00\;\frac{{\rm{m}}}{{{{\rm{s}}^2}}}\)
\({v_s} = 145\;\frac{{{\rm{km}}}}{{\rm{h}}}\)