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Physics: Principles with Applications | 6th Edition | ISBN: 9780321569837 | Authors: Douglas C. Giancoli
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The burning of gasoline in a car releases about 3.0 × 104kcal/gal. If a car averages 41

Chapter 15, Problem 59GP

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QUESTION:

Problem 59GP

The burning of gasoline in a car releases about 3.0 × 104kcal/gal. If a car averages 41 km/gal when driving 90 km/h, which requires 25 hp, what is the efficiency of the engine under those conditions?

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QUESTION:

Problem 59GP

The burning of gasoline in a car releases about 3.0 × 104kcal/gal. If a car averages 41 km/gal when driving 90 km/h, which requires 25 hp, what is the efficiency of the engine under those conditions?

ANSWER:

Solution 59P

Step 1 of 2:

A car running on gasoline releases an energy QH and it runs at an average speed of 90 km/h. The mileage is given by 41 km/gal. The power required by the car is 25 hp. We are going to find the efficiency of the engine.

The power of the car is P =W/t  = 25 hp = 25 x 746 J/s

The mileage of the car M = 41 km/gal

The speed of the car v = 90 km/h

The gasoline-equivalent gallon GGE = 3x104 kcal/gal

The heat released by the car is not directly given. We need to find it by using the given data.

The heat released by the car per hour is expressed as

The heat released by the car per second is expressed as

Replacing the kcal/s to J/s

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