Bone Density Test. In Exercises, assume that scores on a bone mineral density test are normally distributed with a mean of 0 and a standard deviation of 1.

For a randomly selected subject, find the probability of a score greater than –1.

## Problem 4CQQ

Answer:

Step1 of 3:

We have the scores on a bone mineral density test are normally distributed with a mean of 0 and a standard deviation of 1.

Step2 of 3:

We need to find the probability of a score greater than –1.

Step3 of 3:

The probability of a score greater than –1 can be calculated by using complement rule and it is given by

P(z > -1) = 1 - P(z < -1)

= 1 - 0.1587

= 0.8413.

Probability that -1 is calculated by using standard normal table(area under normal curve).in statistical table we have to see row -1.0 under column 0.00

Hence, P(z < -1) = 0.1587

Therefore,The probability of a score greater than –1 is 0.8413.