Solution Found!
Count Five Test for Comparing Variation in Two
Chapter 9, Problem 19 BB(choose chapter or problem)
Count Five Test for Comparing Variation in Two Populations Use the original weights of pre1964 quarters and post1964 quarters listed in Data Set 21 in Appendix B. Instead of using the F test, use the following procedure for a “count five” test of equal variation. What do you conclude?
a. For the first sample, find the absolute deviation of each value. The absolute deviation of a sample value x is \(\mathrm {|\ x - x^-\ |}\) . Sort the absolute deviation
values. Do the same for the second sample.
b. Let c 1 be the count of the number of absolute deviation values in the first sample that are greater than the largest absolute deviation value in the other sample. Also, let c 2 be the count of the number of absolute deviation values in the second sample that are greater than the largest absolute deviation value in the other sample. (One of these counts will always be zero.)
c. If the sample sizes are equal ( n 1 = n 2 ) , use a critical value of 5. If \(\mathrm {n\ 1 \ne n\ 2}\) , calculate the critical value shown below.
\(\log\ (\ \alpha\ /\ 2\ )\ \ \log \mathrm{(\ n\ 1\ n\ 1\ + n\ 2\ )}\)
d. If \(\mathrm {c\ 1\ \geq\ critical\ value}\), then conclude that \(\mathrm {\sigma\ 1\ 2 > \sigma\ 2\ 2}\) . If \(\mathrm {c\ 2\ \geq\ critical\ value}\), then conclude that \(\mathrm {\sigma\ 2\ 2 > \sigma\ 1\ 2}\) . Otherwise, fail to reject the null hypothesis of \(\mathrm {\sigma\ 1\ 2 > \sigma\ 2\ 2}\) .
Equation Transcription:
Text Transcription:
| x - x^- |
( n 1 = n 2 )
n 1 {not=}n 2
log (alpha / 2) log (n 1 n 1 + n 2 )
c {>/=} 1 critical value
sigma 1 2 > sigma 2 2
c {>/=} 2 critical value
sigma 2 2 > sigma 1 2
sigma 1 2 = sigma 2 2
Questions & Answers
QUESTION:
Count Five Test for Comparing Variation in Two Populations Use the original weights of pre1964 quarters and post1964 quarters listed in Data Set 21 in Appendix B. Instead of using the F test, use the following procedure for a “count five” test of equal variation. What do you conclude?
a. For the first sample, find the absolute deviation of each value. The absolute deviation of a sample value x is \(\mathrm {|\ x - x^-\ |}\) . Sort the absolute deviation
values. Do the same for the second sample.
b. Let c 1 be the count of the number of absolute deviation values in the first sample that are greater than the largest absolute deviation value in the other sample. Also, let c 2 be the count of the number of absolute deviation values in the second sample that are greater than the largest absolute deviation value in the other sample. (One of these counts will always be zero.)
c. If the sample sizes are equal ( n 1 = n 2 ) , use a critical value of 5. If \(\mathrm {n\ 1 \ne n\ 2}\) , calculate the critical value shown below.
\(\log\ (\ \alpha\ /\ 2\ )\ \ \log \mathrm{(\ n\ 1\ n\ 1\ + n\ 2\ )}\)
d. If \(\mathrm {c\ 1\ \geq\ critical\ value}\), then conclude that \(\mathrm {\sigma\ 1\ 2 > \sigma\ 2\ 2}\) . If \(\mathrm {c\ 2\ \geq\ critical\ value}\), then conclude that \(\mathrm {\sigma\ 2\ 2 > \sigma\ 1\ 2}\) . Otherwise, fail to reject the null hypothesis of \(\mathrm {\sigma\ 1\ 2 > \sigma\ 2\ 2}\) .
Equation Transcription:
Text Transcription:
| x - x^- |
( n 1 = n 2 )
n 1 {not=}n 2
log (alpha / 2) log (n 1 n 1 + n 2 )
c {>/=} 1 critical value
sigma 1 2 > sigma 2 2
c {>/=} 2 critical value
sigma 2 2 > sigma 1 2
sigma 1 2 = sigma 2 2
ANSWER:
Answer :
Step 1 of 1 :
a).
Given use the weights (g) of pre-1964 quarters and post-1964 quarters listed in Data Set 21 of Appendix B.
The table is given below.
Pre-1964 Quarters |
Pre-1964 Quarters |
||||
6.2771 |
0.084427 |
0.084427 |
6.2674 |
0.074727 |
0.074727 |
6.2371 |
0.044427 |
0.044427 |
6.2718 |
0.079127 |
0.079127 |
6.1501 |
-0.04257 |
0.04257 |
6.1949 |
0.002227 |
0.002227 |
6.0002 |
-0.19247 |
0.19247 |