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Get Full Access to Elementary Statistics - 12 Edition - Chapter 13.2 - Problem 5 bsc
Get Full Access to Elementary Statistics - 12 Edition - Chapter 13.2 - Problem 5 bsc

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# Assume that matched pairs of data result in | Ch 13.2 - 5 BSC ISBN: 9780321836960 18

## Solution for problem 5 BSC Chapter 13.2

Elementary Statistics | 12th Edition

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Problem 5 BSC

Problem 5BSC

Assume that matched pairs of data result in the given number of signs when the value of the second variable is subtracted from the corresponding value of the first variable. Use the sign test with a 0.05 significance level to test the null hypothesis of no difference.

Positive signs: 13; negative signs: 1; ties: 0 (from a preliminary test of the MicroSort method of gender selection)

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Step 1 of 3

Solution 5BSC

The null hypothesis is the claim of no difference between the gender selections.

H0: There is no difference between the gender selections.

H1: There is a difference between the gender selections.

Its given that the number of positive signs = 13

Number of negative signs = 1

Number of ties = 0

So the Sample size that is used for the sign test n = 14

As the sample size n = 14 is less than 25 that is .

Therefore the value of the test statics is the number of times the less frequent sign occurs which in present case is the negative sign.

Thus value of the test statics x = 1.

As the test is a two tailed test, with n = 14 and a = 0.05 significance level , the critical value is 2.

But x = 1, which is less than 2. So the critical value is greater than the number of times less frequent sign occurs.

Hence, the Null hypothesis is rejected. And the alternative hypothesis is accepted

That is there is a difference.

Interpretation : Therefore, it can be said that there is a difference in the gender selection.

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321836960

The answer to “Assume that matched pairs of data result in the given number of signs when the value of the second variable is subtracted from the corresponding value of the first variable. Use the sign test with a 0.05 significance level to test the null hypothesis of no difference.Positive signs: 13; negative signs: 1; ties: 0 (from a preliminary test of the MicroSort method of gender selection)” is broken down into a number of easy to follow steps, and 65 words. This textbook survival guide was created for the textbook: Elementary Statistics, edition: 12. The full step-by-step solution to problem: 5 BSC from chapter: 13.2 was answered by , our top Statistics solution expert on 03/15/17, 10:30PM. This full solution covers the following key subjects: signs, test, variable, null, difference. This expansive textbook survival guide covers 121 chapters, and 3629 solutions. Elementary Statistics was written by and is associated to the ISBN: 9780321836960. Since the solution to 5 BSC from 13.2 chapter was answered, more than 282 students have viewed the full step-by-step answer.

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