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Starting from the front door of a ranch house, you walk

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 5E Chapter 2

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 5E

Starting from the front door of a ranch house, you walk 60.0 m due east to a windmill, turn around, and then slowly walk 40.0 m west to a bench, where you sit and watch the sunrise. It takes you 28.0 s to walk from the house to the windmill and then 36.0 s to walk from the windmill to the bench. For the entire trip from the front door to the bench, what are your (a) average velocity and (b) average speed?

Step-by-Step Solution:
Step 1 of 3

Solution 5E Let us have a look at the figure below. Let us understand your walk as shown in the figure above. (a) Your displacement = 60 m 40 m = 20 m 20 m is the shortest distance between your door and the bench. Time needed by you to go to the windmill and then back to the bench is = (28.0 + 36.0) s = 64 s Now, Average velocity = Displacement/Time = 20 m/64 s = 0.3125 m/s (b) Total distance covered by you in walking from your house to the windmill and then to the bench is = 60 m + 40 m = 100 m Now, Average speed = Total distance/Time = 100 m/64 s = 1.5625 m/s

Step 2 of 3

Chapter 2, Problem 5E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Starting from the front door of a ranch house, you walk