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Freshman 15 The “Freshman 15” refers to the urban legend
Chapter 9, Problem 25BSC(choose chapter or problem)
Freshman 15 The “Freshman 15” refers to the urban legend that is the common belief that students gain an average of 15 lb (or 6.8 kg) during their freshman year. Refer to Data Set 4 in Appendix B and consider the sample values in this format: ( April weight ) − ( September weight). In this format, positive differences represent gains in weight, and negative differences represent losses of weight. If we use \(\mu\) d to denote the mean of the “ April − September ” differences in weights of college students during their freshman year, the “Freshman 15” is the claim that \(\mathrm {\mu\ d=15\ lb }\) or \(\mathrm {\mu\ d=6.8\ kg}\) . Test the claim that \(\mathrm {\mu\ d=6.8\ kg}\) using a 0.05 significance level with the 67 subjects from Data Set 4 in Appendix B. What do these results suggest about the “Freshman 15”?
Equation Transcription:
Text Transcription:
mu d
mu d=15 lb
mu d=6.8 kg
mu d=6.8 kg
Questions & Answers
QUESTION:
Freshman 15 The “Freshman 15” refers to the urban legend that is the common belief that students gain an average of 15 lb (or 6.8 kg) during their freshman year. Refer to Data Set 4 in Appendix B and consider the sample values in this format: ( April weight ) − ( September weight). In this format, positive differences represent gains in weight, and negative differences represent losses of weight. If we use \(\mu\) d to denote the mean of the “ April − September ” differences in weights of college students during their freshman year, the “Freshman 15” is the claim that \(\mathrm {\mu\ d=15\ lb }\) or \(\mathrm {\mu\ d=6.8\ kg}\) . Test the claim that \(\mathrm {\mu\ d=6.8\ kg}\) using a 0.05 significance level with the 67 subjects from Data Set 4 in Appendix B. What do these results suggest about the “Freshman 15”?
Equation Transcription:
Text Transcription:
mu d
mu d=15 lb
mu d=6.8 kg
mu d=6.8 kg
ANSWER:
Solution 25BB
Using degrees of freedom of , from the table of t
