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CALC A web page designer creates an animation in which a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 3E Chapter 3

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 3E

CALC? A web page designer creates an animation in which a dot on a computer screen has position (a) Find the magnitude and direction of the dot’s average velocity between t = 0 and t = 2.0 s.(b) Find the magnitude and direction of the instantaneous velocity at t = 0, t = 1.0 s, and t = 2.0 s. (c) Sketch the dot’s trajectory from t = 0 to t = 2.0 s, and show the velocities calculated in part (b).

Step-by-Step Solution:
Step 1 of 3

Solution 3E Given that Now, position vector at time t= 0s is r (0) = [4.0 cm + 0] i + 0 r (0) = 4.0 cm i Position vector at time t = 2.0 s is r (2.0) = [4.0 cm + 10.0 cm] i + 10 cm j r(2.0) = 14 cm i + 10 cm j r(2.0)r(0) Therefore, average velocity is =2.00 cm/s 14 cm i +10 cm j 4.0 cm j Average velocity = 2 s Average velocity = 5 cm/s i + 5 cm/s j (a) The magnitude of this velocity s = 5 + 5 cm/s = 52 cm/s Let be the angle made by the velocity vector with the x-axis. tan = 5/5 tan = 1 0 = 45 0 Therefore, the velocity vector makes an angle of 45 with the horizontal axis. (b) Differentiating the expression for r with respect to t, v = 5t cm/s i + 5.00 cm/s j When time t = 0, v (0) = 5.00 cm/s j Therefore, the magnitude of this velocity is 5.00 cm/s. 0 Since this velocity has only j component, hence it will make an angle owith the x-axis. Again, we have v = 5t cm/s i + 5.00 cm/s j When t = 1.0 s v(1.0 s) = 5.00 cm/s i + 5.00 cm/s j 2 2 The magnitude of this velocity s = 5 + 5cm/s = 52 cm/s = 7.07 cm/s The angle made by this velocity vector with the x-component is tan 1= 5/5 , if 1 is the angle. tan = 1 1 0 1 45 We have v = 5t cm/s i + 5.00 cm/s j When t = 2.0 s v (2.0s) = 10.0 cm/s i + 5.00 cm/s j The magnitude of this velocity vector is 10 + 5 cm/s = 55 cm/s = 11.18 cm/s If 2 be the angle made by this velocity vector with the x-axis, tan = 5/10 2 = 26.56 0 2 0 So, the angle made by the above velocity vector with the x-axis is 26.56 . (c) The sketch of trajectory can be done as shown below.

Step 2 of 3

Chapter 3, Problem 3E is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 3E from 3 chapter was answered, more than 945 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Dot, Find, velocity, magnitude, direction. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. The answer to “CALC? A web page designer creates an animation in which a dot on a computer screen has position (a) Find the magnitude and direction of the dot’s average velocity between t = 0 and t = 2.0 s.(b) Find the magnitude and direction of the instantaneous velocity at t = 0, t = 1.0 s, and t = 2.0 s. (c) Sketch the dot’s trajectory from t = 0 to t = 2.0 s, and show the velocities calculated in part (b).” is broken down into a number of easy to follow steps, and 82 words. The full step-by-step solution to problem: 3E from chapter: 3 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13.

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