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If a jumping frog can give itself the same initial speed

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 8DQ Chapter 3

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 8DQ

If a jumping frog can give itself the same initial speed regardless of the direction in which it jumps (forward or straight up), how is the maximum vertical height to which it can jump related to its maximum horizontal range Rmax = v20/g?

Step-by-Step Solution:

Solution 8DQ Step 1: The equation for the maximum range of a projectile is, R = v sin 2 / g 0 Where, v - initial velocity with which the projectile is thrown 0 - Angle it made with the x-axis g - acceleration due to gravity In the question, they have provided, R = v /g max 0 Comparing both equations, we can see that, sin 2 = 1 2 = sin (1)1 2 = 90° = 45°

Step 2 of 2

Chapter 3, Problem 8DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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If a jumping frog can give itself the same initial speed