Problem 8DQ
If a jumping frog can give itself the same initial speed regardless of the direction in which it jumps (forward or straight up), how is the maximum vertical height to which it can jump related to its maximum horizontal range Rmax = v20/g?
Step-by-Step Solution:
Solution 8DQ Step 1: The equation for the maximum range of a projectile is, R = v sin 2 / g 0 Where, v - initial velocity with which the projectile is thrown 0 - Angle it made with the x-axis g - acceleration due to gravity In the question, they have provided, R = v /g max 0 Comparing both equations, we can see that, sin 2 = 1 2 = sin (1)1 2 = 90° = 45°
Step 2 of 2
