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A Ferris wheel with radius 14.0 m is turning about a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 29E Chapter 3

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 29E

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center (Fig). The linear speed of a passenger on the rim is constant and equal to 7.00 m/s. What are the magnitude and direction of the passenger’ acceleration as she passes through (a) the lowest point in her circular motion? (b) The highest point in her circular motion? (c) How much time does it take the Ferris wheel to make one revolution? Figure:

Step-by-Step Solution:

Solution 29E Step 1: Given data Radius of Ferris wheel ( r ) = 14m Linear speed of a passenger on the rim (v) = 7 m/s (constant) Step 2: To find the magnitude and direction of the acceleration At lowest point Acceleration a = v2 l r 7*7 = 14 a l = 3.5 m/s (upward) Acceleration in the uniform circular motion is always directed towards the center of the circle and it is called centripetal acceleration. From the above statement acceleration at the lowest point will be upward.

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Chapter 3, Problem 29E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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