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Physics / Sears and Zemansky's University Physics with Modern Physics 13 / Chapter 9 / Problem 28E

Sears and Zemansky's University Physics with Modern Physics | 13th Edition | ISBN: 9780321696861 | Authors: Hugh D. Young; Roger A. Freedman; A. Lewis Ford

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Solved: At t = 3.00 s a point on the rim of a

Chapter 9, Problem 28E

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QUESTION:

Problem 28E

At t = 3.00 s a point on the rim of a 0.200-m-radius wheel has a tangential speed of 50.0 m/s as the wheel slows down with a tangential acceleration of constant magnitude 10.0 m/s2. (a) Calculate the wheel’s constant angular acceleration. (b) Calculate the angular velocities at t = 3.00 s and t = 0. (c) Through what angle did the wheel turn between t = 0 and t = 3.00 s? (d) At what time will the radial acceleration equal g?

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QUESTION:

Problem 28E

At t = 3.00 s a point on the rim of a 0.200-m-radius wheel has a tangential speed of 50.0 m/s as the wheel slows down with a tangential acceleration of constant magnitude 10.0 m/s2. (a) Calculate the wheel’s constant angular acceleration. (b) Calculate the angular velocities at t = 3.00 s and t = 0. (c) Through what angle did the wheel turn between t = 0 and t = 3.00 s? (d) At what time will the radial acceleration equal g?

ANSWER:

Solution 28E

Problem (a)

Step 1:

Radius of the rim r = 0.200 m

Tangential speed v = 50.0 m/s

Time t = 3.00 s

Tangential acceleration a = -10.0m/s2 (slows down)

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