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Chapter 7, Problem 11RE

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QUESTION:

Problem 11RE

Wechsler Intelligence Scale The Wechsler Intelligence Scale for Children is approximately normally distributed, with mean 100 and standard deviation 15.

(a) What is the probability that a randomly selected test taker will score above 125?

(b) What is the probability that a randomly selected test taker will score below 90?

(c) What proportion of test takers will score between 110 and 140?

(d) If a child is randomly selected, what is the probability that she scores above 150?

(e) What intelligence score will place a child in the 98th percentile?

(f) If normal intelligence is defined as scoring in the middle 95% of all test takers, figure out the scores that differentiate normal intelligence from abnormal intelligence.

Questions & Answers

QUESTION:

Problem 11RE

Wechsler Intelligence Scale The Wechsler Intelligence Scale for Children is approximately normally distributed, with mean 100 and standard deviation 15.

(a) What is the probability that a randomly selected test taker will score above 125?

(b) What is the probability that a randomly selected test taker will score below 90?

(c) What proportion of test takers will score between 110 and 140?

(d) If a child is randomly selected, what is the probability that she scores above 150?

(e) What intelligence score will place a child in the 98th percentile?

(f) If normal intelligence is defined as scoring in the middle 95% of all test takers, figure out the scores that differentiate normal intelligence from abnormal intelligence.

ANSWER:

Problem 11RE

Answer:

Step1 of 2:

We have The Wechsler Intelligence Scale for Children is approximately normally distributed, with mean 100 and standard deviation 15.

a).

The probability that a randomly selected test taker will score above 125 is P(X > 125)

Now,

P(X > 125) = 1 - P(X < 125)

                   = 1 - P(<)

                   = 1 - P(Z < 1.66)

                   = 1 - 0.9515

                     = 0.0475.

Therefore,The probability that a randomly selected test taker will score above 125 is

P(X > 125) = 0.0475.

b).

The probability that a randomly selected test taker will score below 90 is P(X < 90)

Now,

P(X < 90)  = P(X < 90)

                  = P(<)

                  = P(Z < -0.6666)

                  =  0.2546.

Therefore,The probability that a randomly selected test taker will score below 90 is

P(X < 90) = 0.2546.

c).

Proportion of test takers will score between 110 and 140 is P(110 140)

Now,

P(110 < X <140) =  P(110 < X < 140)

P(= P(0.6666 < Z < 2.6666)

P(Z < 2.666) = 0.9961  (Area Under Normal Curve table)

P(Z > 0.666) = 0.7454  (Area Under Normal Curve table)

P(Z < 2.666) - P(Z > 0.666) = 0.9961 - 0.7454 = 0.2507.

Therefore,Proportion of test takers will score between 110 and 140 is

P(110 140) = 0.2507.

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