Forces act at a point. The magnitude of is 9.00 N, and its direction is 60.0o above the x-axis in the second quadrant. The magnitude of is 6.00 N, and its direction is 53.1o below the x-axis in the third quadrant. (a) What are the x- and y-components of the resultant force? (b) What is the magnitude of the resultant force?

Solution 6E Step 1: According to the question, the vectors lie in this manner on the coordinate system. 0 The total angle between these two forces is, 60 + 53.1 = 113.1 . The resultant vector’s magnitude we can find by, R = F 12+ F 22+ 2F 1 2os = + 6 + 2 × 9 × 6 × cos 113.1 0 = 81 + 36 42.37 = 72.648 = 8.523N STEP 2: As we got the resultant, it’s not a big deal to find the angle it makes with the horizontal axis. By the parallelogram law of vector addition, F + F = R 1 2 2 2 F =2R F = 1 R + F 1 2 × R × F1×...