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Textbooks / Physics / University Physics 13 / Chapter 4 / Problem 9E

A box rests on a frozen pond, which serves as a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 9E Chapter 4

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 9E

A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.0 N to the box and produces an acceleration of magnitude 3.00 m/s2, what is the mass of the box?

Step-by-Step Solution:
Step 1 of 3

Solution 9E Given that the force F = 48.0 N Acceleration a = 3.00 m/s 2 Let m be the mass of the box. From Newton’s second law of motion, F = ma 48.0 N = m × 3.00 m/s 2 m = 48.0/3.00 kg m = 16.0 kg The mass of the box is 16.0 kg .

Step 2 of 3

Chapter 4, Problem 9E is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

This full solution covers the following key subjects: box, magnitude, horizontal, acceleration, Force. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.0 N to the box and produces an acceleration of magnitude 3.00 m/s2, what is the mass of the box?” is broken down into a number of easy to follow steps, and 43 words. Since the solution to 9E from 4 chapter was answered, more than 1183 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 9E from chapter: 4 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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