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BIO World-class sprinters can accelerate out of the

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 21E Chapter 4

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 21E

BIO? World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15 m/s2. How much horizontal force must a 55-kg sprinter exert on the starting blocks to produce this acceleration? Which body exerts the force that propels the sprinter: the blocks or the sprinter herself?

Step-by-Step Solution:
Step 1 of 3

Solution 21E According to newton’s second law of motion,the net force acting on an object of mass m,produces an acceleration a. Newton’s second law F = ma. Here m is the mass and a is acceleration....

Step 2 of 3

Chapter 4, Problem 21E is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The full step-by-step solution to problem: 21E from chapter: 4 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: blocks, sprinter, horizontal, starting, acceleration. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. The answer to “BIO? World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15 m/s2. How much horizontal force must a 55-kg sprinter exert on the starting blocks to produce this acceleration? Which body exerts the force that propels the sprinter: the blocks or the sprinter herself?” is broken down into a number of easy to follow steps, and 54 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 21E from 4 chapter was answered, more than 284 students have viewed the full step-by-step answer.

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