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# The upward normal force exerted by the floor is 620 N on ISBN: 9780321675460 31

## Solution for problem 24E Chapter 4

University Physics | 13th Edition

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Problem 24E

The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. What are the reaction forces to these two forces? Is the passenger accelerating? If so, what are the magnitude and direction of the acceleration?

Step-by-Step Solution:

Solution 24 E Step 1 : In this question , we need to find the Reaction force of upward and downward forces Is the passenger in the lift acceleration Magnitude and direction of acceleration Step 2 : Considering the data given Upward force F up = 620 N Downward force F down = 650 N Let us find the reaction force This can be obtained using F up F down = mass × acceleration Hence we have Acceleration for the lift is given by gravitational force 2 a = g = 9.8 m/s Substituting the values we get 620 N 650 N = mass × 9.8 m/s 2 Hence the reaction between the forces will be 620 N 650 N = mass × 9.8 m/s 2

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##### ISBN: 9780321675460

University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 24E from chapter: 4 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. What are the reaction forces to these two forces? Is the passenger accelerating? If so, what are the magnitude and direction of the acceleration?” is broken down into a number of easy to follow steps, and 43 words. Since the solution to 24E from 4 chapter was answered, more than 398 students have viewed the full step-by-step answer. This full solution covers the following key subjects: forces, passenger, accelerating, elevator, exerted. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

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