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A horse is hitched to a wagon. Since the wagon pulls back

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 28DQ Chapter 4

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 28DQ

A horse is hitched to a wagon. Since the wagon pulls back on the horse just as hard as the horse pulls on the wagon, why doesn’t the wagon remain in equilibrium, no matter how hard the horse pulls?

Step-by-Step Solution:

Solution 28DQ Step 1: Horse is applying a force on the wagon. Since, it is applying a force, there will be a change of state of the cart and the inertia of the cart will try to prevent it from the state of motion. The cart is coming into contact with the ground with two wheels. So, according to Newton’s third law, every action, there is an equal and opposite reaction. Action is the pulling effect by the horse and the reaction is the frictional force and inertia exerted by the ground on the wheels of the cart. The action reaction pairs will be equal and opposite. But, it does not mean that, the cart will come into the equilibrium state. Consider the case of rocket propulsion. Here, the action and reaction are same but, the rocket is moving up. While the horse is pulling the cart, initially, it should apply a force more enough to overcome the frictional force and inertia. Once, the horse applied that force, the cart will come into motion and thus, the action reaction pair will occur in between the wheels and ground.

Step 2 of 1

Chapter 4, Problem 28DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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A horse is hitched to a wagon. Since the wagon pulls back