CP? A .22-caliber rifle bullet traveling at 350 m/s strikes a large tree and penetrates it to a depth of 0.130 m. The mass of the bullet is 1.80 g. Assume a constant retarding force. (a) How much time is required for the bullet to stop? (b) What force, in newtons, does the tree exert on the bullet?

Solution 30E Step 1 of 5: Given data, Mass of the bullet, m=1.8 g Using 1g = 10 kg m = 0.0018 kg Initial speed of bullet, u= 350 m/s Penetrating depth is the distance, s= 0.13 m Since the bullet should stop at the penetrating depth, the final velocity will be zero, v=0 As shown in the figure below,