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Answer: On-Time Flights According to flightstats.com,

Fundamentals of Statistics | 4th Edition | ISBN: 9780321838704 | Authors: Michael Sullivan,III ISBN: 9780321838704 30

Solution for problem 35AYU Chapter 6.2

Fundamentals of Statistics | 4th Edition

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Fundamentals of Statistics | 4th Edition | ISBN: 9780321838704 | Authors: Michael Sullivan,III

Fundamentals of Statistics | 4th Edition

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Problem 35AYU

On-Time Flights According to flightstats.com, American Airlines flights from Dallas to Chicago are on time 80% of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded.

(a) Explain why this is a binomial experiment.

(b) Find and interpret the probability that exactly 10 flights are on time.

(c) Find and interpret the probability that fewer than 10 flights are on time.

(d) Find and interpret the probability that at least 10 flights are on time.

(e) Find and interpret the probability that between 8 and 10 flights, inclusive, are on time.

Step-by-Step Solution:
Step 1 of 2

Step1 of 2

We have According to flightstats.com, American Airlines flights from Dallas to Chicago are on time 80% of the time. Suppose 15 flights are randomly selected, and the number of on-time flights is recorded.

a).

This is a binomial experiment because:    

1.  It is performed a fixed number of times, n = 15.    

2.  The trials are independent.    

3.  For each trial, there are two possible mutually exclusive outcomes: on time and not on time.    

4.  The probability of “on time” is fixed at p = 0.80.

b).

We have X  B(15, 0.80).

Probability mass function of binomial distribution is given by

P(X) = , x = 0,1,2,.....,15.

We need to find P(3) = ?.

Consider,

P(X)  = , x = 0,1,2,.....,15.

P(10)   =

         =  3003*(0.1073)*(0.00032)

         = 0.103111

         0.1032.    

Therefore,the probability of x successes in the n independent trials of the experiment is P(38) = 0.1032.

In 100 trials of this experiment, we expect about 10 trials to result in exactly 10 flights being on time.

c).

The probability that fewer than 10 flights are on time is given by P(X < 10)

Probability mass function of binomial distribution is given by

P(X) = , x = 0,1,2,.....,15.

P(X) = , x = 0,1,2,.....,15.

Put x = 0,1,2,.....,9. In above equation we get  P(X < 10)

x

P(X)

0

3.2768E-11

1

1.9661E-09

2

5.505E-08

3

9.542E-07

4

1.145E-05

5

0.00010076

6

0.00067176

7

0.00345476

8

0.01381906

9

0.04299262

P(X < 10 ) = 0.06105143

Therefore,The probability that fewer than 10 flights are on time is P(X < 10 ) = 0.06105143.

In 100 trials of this experiment, we expect about 6 trials to result in fewer than 10 flights being on time.

____________

Step 2 of 2

Chapter 6.2, Problem 35AYU is Solved
Textbook: Fundamentals of Statistics
Edition: 4
Author: Michael Sullivan,III
ISBN: 9780321838704

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Answer: On-Time Flights According to flightstats.com,