×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide

CP A 6.50-kg instrument is hanging by a vertical wire

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 47P Chapter 4

University Physics | 13th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 1 314 Reviews
22
0
Problem 47P

CP? A 6.50-kg instrument is hanging by a vertical wire inside a spaceship that is blasting off from rest at the earth’s sur-face. This spaceship reaches an altitude of 276 m in 15.0 s with constant acceleration. (a) Draw a free-body diagram for the instrument during this time. Indicate which force is greater. (b) Find the force that the wire exerts on the instrument.

Step-by-Step Solution:

Solution 47P Step 1 of 5: Given data, Mass of the instrument, m = 6.5 kg Distance, s= 276 m Time taken, t= 15 s Vertical component,(Since motion of spaceship is along vertical direction) Initial velocity, u= 0 Acceleration due to gravity, a 1 g = 9.8 m/s 2 Step 2 of 5: (a) Draw a free-body diagram for the instrument during this time. Indicate which force is greater. Above figure shows the FBD for the instrument in spaceship. The tension force is greater than the weight of the instrument as the acceleration of the spaceship is upward as shown in the above figure. Step 3 of 5: (b) ind the force that the wire exerts on the instrument. The net acceleration of the instrument is due to both acceleration due to gravity and the due acceleration of the the spaceship. To calculate the acceleration of the instrument due to motion of space ship, Using kinematics formula, s= ut + a t 2 2 1 1 2 Since u= 0, s= a2t1 solving for acceleration, a1= 22s t Substituting s= 276 m, t= 15 s 2 (276 m) a1= (15 s) a =2.45 m/s 2 1

Step 4 of 5

Chapter 4, Problem 47P is Solved
Step 5 of 5

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

CP A 6.50-kg instrument is hanging by a vertical wire

×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide
×
Reset your password