Answer: Interference of Triangular Pulses. Two triangular

QUESTION:

Interference of Triangular Pulses. Two triangular wave pulses are traveling toward each other on a stretched string as shown in Fig. E15.32. Each pulse is identical to the other and travels at \(2.00 \mathrm{~cm} / \mathrm{s}\). The leading edges of the pulses are \(1.00 \mathrm{~cm}\) apart at Sketch the shape of the string at

\(t=0.250 \mathrm{~s}, t=0.500 \mathrm{~s}, t=0.750 \mathrm{~s}, t=1.000 \mathrm{~s}, \text { and } t=1.250 \mathrm{~s}\).

Equation Transcription:

Text Transcription:

2.00 cm/s    

1.00 cm  

t=0.250 s, t=0.500 s, t=0.750 s, t=1.000 s, and t=1.250 s

v=2.00 cm/s

v=2.00 cm/s

1.00 cm