Solution Found!
Solved: CP CALC A deep-sea diver is suspended beneath the
Chapter 15, Problem 84CP(choose chapter or problem)
CP CALC A deep-sea diver is suspended beneath the surface of Loch Ness by a 100-m-long cable that is attached to a boat on the surface (Fig. P15.84). The diver and his suit have a total mass of 120 kg and a volume of 0.800 \(\mathrm{m}^{3}\). The cable has a diameter of 2.00 cm and a linear mass density of \(\mu=1.10 \mathrm{~kg} / \mathrm{m}\). The diver thinks he sees something moving in the murky depths and jerks the end of the cable back and forth to send transverse waves up the cable as a signal to his companions in the boat. (a) What is the tension in the cable at its lower end, where it is attached to the diver? Do not forget to include the buoyant force that the water (density 1000 \(\mathrm{kg} / \mathrm{m}^{3}\)) exerts on him. (b) Calculate the tension in the cable a distance above the diver. The buoyant force on the cable must be included in your calculation. (c) The speed of transverse waves on the cable is given by \(v=\sqrt{F / \mu}\) (Eq. 15.13). The speed therefore varies along the cable, since the tension is not constant. (This expression neglects the damping force that the water exerts on the moving cable.) Integrate to find the time required for the first signal to reach the surface.
Equation Transcription:
Text Transcription:
m3
kg/m3
u=1.10 kg/m
v=sqrt F/u
Questions & Answers
QUESTION:
CP CALC A deep-sea diver is suspended beneath the surface of Loch Ness by a 100-m-long cable that is attached to a boat on the surface (Fig. P15.84). The diver and his suit have a total mass of 120 kg and a volume of 0.800 \(\mathrm{m}^{3}\). The cable has a diameter of 2.00 cm and a linear mass density of \(\mu=1.10 \mathrm{~kg} / \mathrm{m}\). The diver thinks he sees something moving in the murky depths and jerks the end of the cable back and forth to send transverse waves up the cable as a signal to his companions in the boat. (a) What is the tension in the cable at its lower end, where it is attached to the diver? Do not forget to include the buoyant force that the water (density 1000 \(\mathrm{kg} / \mathrm{m}^{3}\)) exerts on him. (b) Calculate the tension in the cable a distance above the diver. The buoyant force on the cable must be included in your calculation. (c) The speed of transverse waves on the cable is given by \(v=\sqrt{F / \mu}\) (Eq. 15.13). The speed therefore varies along the cable, since the tension is not constant. (This expression neglects the damping force that the water exerts on the moving cable.) Integrate to find the time required for the first signal to reach the surface.
Equation Transcription:
Text Transcription:
m3
kg/m3
u=1.10 kg/m
v=sqrt F/u
ANSWER:Solution 84CP
Step 1 of 10:
Given data,
- Density of water,
- Volume of diver, V=0.08
- Mass of the diver, M=120 kg
- Acceleration due to gravity, g=9.8
- Mass per unit length of cable, =1.1 kg/m
- Diameter of cable, d=2 cm=0.02 m
Using radius r=(d/2) Radius of cable , r=0.01 m