An object with mass ?m? moves along the ?x?-axis. Its position as a function of time is given by, ?x?(?t?) = ?At? ? ?Bt?3, where ?A? and ?B? are constants. Calculate the net force on the object as a function of time.

Solution 59P Consider an object with mass m moves along the x-axis.its position as a function of time is given by 3 x(t) = At Bt ,where A and B are constants. The net force on the object as a function of time is given by We know that acceleration is the second derivative of the function,so F = ma 2 = m dx /dt 2 dx/dt = A 3Bt a = d/dt(dx/dt) = 6Bt Hence F = 6 mBt