CALC? The position of a training helicopter (weight2.75 X 105 N) in a test is given by Find the net force on the helicopter at t = 5.0 s.

Solution 58P Step 1: The weight of the helicopter is 2.75 × 10 N 5 But we know the weight is defined as the net normal reaction which an object gets. So, 5 mg = 2.75 × 10 m = (2.75 × 10 ) / 9.8 = 28061 kg . The position vector is given as,