A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward with a force whose direction makes an angle of 30.0° with the ramp (Fig.). (a) How large a force is necessary for the component ?Fx?, parallel to the ramp to be 60.0 N? (b) How large will the component ?Fy? perpendicular to the ramp then be? Figure:

Solution to 4E Step 1 Here a slope is at an angle of 20 degrees from the horizontal. A crate is pulled by a man at an angle of 30 degrees with respect to the slope. Thus the free body diagram is as follows, Step 2 Given, F =60N x (a) Resolving the Force vector, F =Fcos …………………………..(1) x FYFsin …………………………....(2) Thus from 1, 60=Fcos30 F=60/cos30 F=69.28N