Two 25.0-N weights are suspended at opposite ends of a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

ISBN: 9780321675460 31

Solution for problem 1E Chapter 5

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 1E

Two 25.0-N weights are suspended at opposite ends of a rope that passes over a light, frictionless pulley. The pulley is attached to a chain from the ceiling. (a) What is the tension in the rope? (b) What is the tension in the chain?

Step-by-Step Solution:

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Solution 1E Let us have a look at the free body diagram as shown below. From the free body diagram as shown above, T + T = 25.0 + 25.0 2T = 50.0 T = 25.0 N (a) Therefore, the tension in the rope is 25.0 N. (b) Let the tension in the chain be T .cThis tension will be balanced by the sum of the two weights. Therefore, T c = 25.0 N + 25.0 N T c= 50.0 N Therefore, the tension in the chain is 50.0 N.

Step 2 of 3

Chapter 5, Problem 1E is Solved

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Textbook: University Physics

Edition: 13

Author: Hugh D. Young, Roger A. Freedman

ISBN: 9780321675460

Since the solution to 1E from 5 chapter was answered, more than 364 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 1E from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: Chain, tension, rope, pulley, opposite. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “Two 25.0-N weights are suspended at opposite ends of a rope that passes over a light, frictionless pulley. The pulley is attached to a chain from the ceiling. (a) What is the tension in the rope? (b) What is the tension in the chain?” is broken down into a number of easy to follow steps, and 44 words. University Physics was written by and is associated to the ISBN: 9780321675460.