A 75.0-kg wrecking ball hangs from a uniform, heavy-duty

Solution 3E Step 1 (a) The tension on a chain due to its own weight, at a point y is given by T (y) = mg(1 y/L) c Here y is measured from the top of the string, m = 26.0 kg is the mass and L is the length of the string. So the total tension will be T ty) = Mg + mg(1 y/L) Here M = 75 kg is the mass of ball. So the maximum tension will be at y = 0, hence the maximum tension is 2 T m = Mg + mg = (M + m)g = (75.0 kg + 26.0 kg)(9.8 m/s ) = 990 N And the minimum tension will be at y = L, and the minimum tension is 2 T min = Mg + mg(1 L/L) = Mg = (75 kg)(9.8 m/s ) = 735 N