Three sleds are being pulled horizontally on frictionless horizontal ice using horizontal ropes (Fig. E5.14). The pull is of magnitude 190 N. Find (a) the acceleration of the system and (b) the tension in ropes A and B.

Solution 14E (a).The masses are tied together and therefore accelerate at the same time. Total mass= 30 kg + 20 kg + 10 kg = 60 kg. According to newton’s second law F = total mass*a Tension =m a * F = m a * 190 N = 60 a * a = 3.17 m/s (b) f the 30 kg and 20 kg sleds are accelerating at 3.17 m/s ,the force pulling them must be F = m * F = 50 kg *.17 m/s 2 F = 158.5 N. Tension in rope A is F = 158.5 N. 2 Same as If the 30 kg being accelerating at 3.17 m/s ,the force pulling them must be F = m a* 2 F = 30 kg *.17 m/s F = 95.1 N. Tension in rope B is F = 95.1N.