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Apparent Weight. A 550-N physics student stands on a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 20E Chapter 5

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 20E

Apparent Weight.? A 550-N physics student stands on a bathroom scale in an elevator that is supported by a cable. The combined mass of student plus elevator is 850 kg. As the elevator starts moving, the scale reads 450 N. (a) Find the acceleration of the elevator (magnitude and direction). (b) What is the acceleration if the scale reads 670 N? (c) If the scale reads zero, should the student worry? Explain. (d) What is the tension in the cable in parts (a) and (c)?

Step-by-Step Solution:

Solution 20E Step 1: Weight of the student on a bathroom scale W 1 = 550 N Combined mass of student and elevator M = 850 kg Problem (a) As the elevator starts moving, find the acceleration of the elevator Step 1: W Mass of the student (m) = g 1 = 59.8 = 56.12 kg Step 2: R = 450 N R = 450 N < W = 550 N 1 Apparent weight of the student is less than the actual weight Hence the elevator moves downward The reaction R = m(g - a ) Step 3: a = g - R m a = 9.8 - 450 56.12 2 Magnitude of acceleration is (a) = 1.78 m/s Direction is downward Problem (b) Step 1: R = 670 N R = 670 N > W 1 = 550 N Apparent weight of the student is greater than the actual weight Hence the elevator moves upward The reaction R = m(g + a ) Step 2: a = R - g m a = 670 - 9.8 56.12 2 Magnitude of acceleration is (a) = 2.13 m/s Direction is upward Problem (c) If the scale reads zero, R = 0 N This shows that a = g, the elevator moves at the rate of free fall, hence the student should worry about this. In this case the the student feels the weightlessness. Problem (d) Step 1: Tension in the cable when a = 1.78 m/s 2 Tension ( T ) = M ( a + g ) M = 850 kg T = 850 ( 1.78 + 9.8 ) T = 9843 N Step 2: Tension in the cable when a = g Here the acceleration is downward, therefore a = -9.8 m/s 2 T = 850 ( -9.8 + 9.8 ) T = 0 The tension in the cable is zero when the elevator moves downward at the acceleration = g. Problem (d) Tension in the cable Step 1: 2 When a = -1.78 m/s T = M ( a+g) Where M is combined mass T = 850 * (-1.78 + 9.8) T = 6817 N

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Chapter 5, Problem 20E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

This textbook survival guide was created for the textbook: University Physics, edition: 13. The full step-by-step solution to problem: 20E from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. The answer to “Apparent Weight.? A 550-N physics student stands on a bathroom scale in an elevator that is supported by a cable. The combined mass of student plus elevator is 850 kg. As the elevator starts moving, the scale reads 450 N. (a) Find the acceleration of the elevator (magnitude and direction). (b) What is the acceleration if the scale reads 670 N? (c) If the scale reads zero, should the student worry? Explain. (d) What is the tension in the cable in parts (a) and (c)?” is broken down into a number of easy to follow steps, and 85 words. Since the solution to 20E from 5 chapter was answered, more than 1203 students have viewed the full step-by-step answer. This full solution covers the following key subjects: elevator, Scale, reads, cable, acceleration. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460.

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