×
Log in to StudySoup

Forgot password? Reset password here

CP CALC A 2540-kg test rocket is launched vertically from

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

Problem 22E Chapter 5

University Physics | 13th Edition

  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 0 309 Reviews
23
4
Problem 22E

CP CALC? A 2540-kg test rocket is launched vertically from the launch pad. Its fuel (of negligible mass) provides a thrust force such that its vertical velocity as a function of time is given by v(t) = At + Bt2 , where A and B are constants and time is measured from the instant the fuel is ignited. The rocket has an upward acceleration of 1.50 m/s2 at the instant of ignition and, 1.00 s later, an upward velocity of 2.00 m/s. (a) Determine A and B , including their SI units. (b) At 4.00 s after fuel ignition, what is the acceleration of the rocket, and (c) what thrust force does the burning fuel exert on it, assuming no air resistance? Express the thrust in newtons and as a multiple of the rocket’s weight. (d) What was the initial thrust due to the fuel?

Step-by-Step Solution:

Solution 22E Step 1 of 6: (a) Determine A and B , including their SI units. Given vertical velocity as the function of time, v = At + Bt ……….1 Solving for A, Differentiating with respect to time, d d 2 dtv = dt(At + Bt ) Using a= v d a = d(At) + (Bt ) 2 dt dt dt a= A+ 2Bt 2 Substituting at t= 0s , a= 1.5m/s 1.5m/s = A+ 0 2 Therefore, A= 1.5m/s Step 2 of 6: Solving for B Substituting A= 1.5m/s ,v=2 m/s at t=1s in equation 1, 2 v = At + Bt 2 m/s=1.5m/s (1s)+ B(1s) 2 2 B (1s) = 2 m/s -1.5 m/s B (1s) = 0.5 m/s B =0.5 m/s 3 3 2 Using B =0.25 m/s and A= 1.5m/s in equation 1 v = (1.5m/s )t + (0.5 m/s )t ………...2 Similarly acceleration equation becomes, a= (1.5m/s )+ 2(0.5 m/s )t 3 a= 1.5+ t…………..3 Step 3 of 6: (b) t 4.00 s after fuel ignition, what is the acceleration of the rocket, In order to calculate the acceleration at t=4s, we need to calculate the velocity at the same instant. Substituting t = 4s in equation 2, v = (1.5m/s )(4 s) + (0.5 m/s )(4 s) 2 V = 8 m/s By fundamental relation of acceleration, a= v t Using V = 7 m/s and t= 4s 8 m/s a = 4 s 2 a= 2 m/s 2 Therefore, acceleration 4s after the fuel ignition is 2 m/s .

Step 4 of 6

Chapter 5, Problem 22E is Solved
Step 5 of 6

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 22E from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: Fuel, thrust, rocket, its, upward. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. Since the solution to 22E from 5 chapter was answered, more than 877 students have viewed the full step-by-step answer. The answer to “CP CALC? A 2540-kg test rocket is launched vertically from the launch pad. Its fuel (of negligible mass) provides a thrust force such that its vertical velocity as a function of time is given by v(t) = At + Bt2 , where A and B are constants and time is measured from the instant the fuel is ignited. The rocket has an upward acceleration of 1.50 m/s2 at the instant of ignition and, 1.00 s later, an upward velocity of 2.00 m/s. (a) Determine A and B , including their SI units. (b) At 4.00 s after fuel ignition, what is the acceleration of the rocket, and (c) what thrust force does the burning fuel exert on it, assuming no air resistance? Express the thrust in newtons and as a multiple of the rocket’s weight. (d) What was the initial thrust due to the fuel?” is broken down into a number of easy to follow steps, and 145 words.

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

CP CALC A 2540-kg test rocket is launched vertically from

×
Log in to StudySoup
Get Full Access to University Physics - 13 Edition - Chapter 5 - Problem 22e

Forgot password? Reset password here

Join StudySoup for FREE
Get Full Access to University Physics - 13 Edition - Chapter 5 - Problem 22e
Join with Email
Already have an account? Login here
Reset your password

I don't want to reset my password

Need an Account? Is not associated with an account
Sign up
We're here to help

Having trouble accessing your account? Let us help you, contact support at +1(510) 944-1054 or support@studysoup.com

Got it, thanks!
Password Reset Request Sent An email has been sent to the email address associated to your account. Follow the link in the email to reset your password. If you're having trouble finding our email please check your spam folder
Got it, thanks!
Already have an Account? Is already in use
Log in
Incorrect Password The password used to log in with this account is incorrect
Try Again

Forgot password? Reset it here