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CP CALC A 2.00-kg box is moving to the right with speed

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 23E Chapter 5

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 23E

CP CALC? A 2.00-kg box is moving to the right with speed 9.00 m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F (t) = (6.00 N/s2)t2. (a) What distance does the box move from its position at t = 0 before its speed is reduced to zero? (b) If the force continues to be applied, what is the speed of the box at t = 3.00 s?

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Solution 23E According to newton’s second law F=ma The force is not constant, so the acceleration is not constant,so we cannot use the kinematic equations. we have to use newton’s second law The box is moving right side so its direction is toward positive x axis F x ax(t)= m (6 N/s )t = 2 kg =(-3 m/s )t 2 To find the velocity as a function of time, integrate the acceleration 4 4 vx(t)=-(1m/s )t +9 m/s To find the velocity as a position of time, integrate the velocity 4 3 x(t)=-(1 m/s )(3 s) +(9 m/s)t a) vx=0 when (1m/s )t =9 m/s 3 9 m/s t = (1m/s ) t= 2.08 s At t= 2.08 s 4 x(t)=(9 m/s)(2.08 s) -(0.250 m/s )=18.72 m-4.68 m=14 m b) At t=3 s 4 3 vx(t)=-(1m/s )(3 s) +9 m/s =-18 m/s The box starts out moving to the right. But because the acceleration is to the left.

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Chapter 5, Problem 23E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The answer to “CP CALC? A 2.00-kg box is moving to the right with speed 9.00 m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F (t) = (6.00 N/s2)t2. (a) What distance does the box move from its position at t = 0 before its speed is reduced to zero? (b) If the force continues to be applied, what is the speed of the box at t = 3.00 s?” is broken down into a number of easy to follow steps, and 87 words. This full solution covers the following key subjects: box, speed, Force, applied, horizontal. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 23E from 5 chapter was answered, more than 3462 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 23E from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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CP CALC A 2.00-kg box is moving to the right with speed