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Solved: For diatomic carbon dioxide gas (CO2, molar mass
Chapter 18, Problem 47E(choose chapter or problem)
QUESTION:
Problem 47E
For diatomic carbon dioxide gas (CO2, molar mass 44.0 g/mol) at T = 300 K, calculate (a) the most probable speed vmp; (b) the average speed vav; (c) the root-mean-square speed rms.
Questions & Answers
QUESTION:
Problem 47E
For diatomic carbon dioxide gas (CO2, molar mass 44.0 g/mol) at T = 300 K, calculate (a) the most probable speed vmp; (b) the average speed vav; (c) the root-mean-square speed rms.
ANSWER:Solution 47E
Step 1:
Molar mass of CO2 = 44.0 g/ mol
1 mol is having avogadro number of molecules in it.
Therefore, 1 mol = NA = 6.023 × 1023 molecules
Therefore, Molar mass of CO2 = 44 g / (6.023 × 1023) = 7.31 × 10-23 g
1 g = 10-3 kg
Therefore, molar mass of CO2 = 7.31 × 10-26 kg