×
Log in to StudySoup

Forgot password? Reset password here

Some sliding rocks approach the base of a hill with a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 30E Chapter 5

University Physics | 13th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 0 408 Reviews
24
5
Problem 30E

Some sliding rocks approach the base of a hill with a speed of 12 m/s. The hill rises at 36° above the horizontal and has coefficients of kinetic friction and static friction of 0.45 and 0.65, respectively, with these rocks. (a) Find the acceleration of the rocks as they slide up the hill. (b) Once a rock reaches its highest point, will it stay there or slide down the hill? If it stays, show why. If it slides, find its acceleration on the way down.

Step-by-Step Solution:
Step 1 of 3

Solution 30E Let us have a look at the following figure. Let the mass of the rocks be m. They are sliding up the hill at an acceleration of a. Since the rocks are sliding up, hence the force of kinetic friction will act downward slope of the hill. If ks the coefficient of kinetic friction, then the frictional force acting on the rocks is F k= mkcos 36 . Moreover, the downward weight on the rocks is mgsin 36 .0 Therefore, the total force acting on the rocks when they are sliding up the hill is F T = mgsin 36 + mgcok 36 0 ma = mgsin 36 + mgcos 36 0 k 0 0 a = gsin 36 + gcks 36 0 0 a = g(sin 36 + cok 36 ) a = 9.80 (0.58 + 0.45 × 0.80) 2 a = 9.21 m/s Therefore, the acceleration of the rocks as they are sliding...

Step 2 of 3

Chapter 5, Problem 30E is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 30E from 5 chapter was answered, more than 329 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “Some sliding rocks approach the base of a hill with a speed of 12 m/s. The hill rises at 36° above the horizontal and has coefficients of kinetic friction and static friction of 0.45 and 0.65, respectively, with these rocks. (a) Find the acceleration of the rocks as they slide up the hill. (b) Once a rock reaches its highest point, will it stay there or slide down the hill? If it stays, show why. If it slides, find its acceleration on the way down.” is broken down into a number of easy to follow steps, and 85 words. The full step-by-step solution to problem: 30E from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: Hill, rocks, down, its, slide. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Some sliding rocks approach the base of a hill with a

×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide

Forgot password? Reset password here

Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide
Join with Email
Already have an account? Login here
Reset your password

I don't want to reset my password

Need an Account? Is not associated with an account
Sign up
We're here to help

Having trouble accessing your account? Let us help you, contact support at +1(510) 944-1054 or support@studysoup.com

Got it, thanks!
Password Reset Request Sent An email has been sent to the email address associated to your account. Follow the link in the email to reset your password. If you're having trouble finding our email please check your spam folder
Got it, thanks!
Already have an Account? Is already in use
Log in
Incorrect Password The password used to log in with this account is incorrect
Try Again

Forgot password? Reset it here