Answer: The plates of a parallel-plate capacitor are 2.50

Chapter 24, Problem 1E

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QUESTION:

Problem 1E

The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00 X 106 V/m. What is (a) the potential difference between the plates; (b) the area of each plate; (c) the capacitance?

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QUESTION:

Problem 1E

The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00 X 106 V/m. What is (a) the potential difference between the plates; (b) the area of each plate; (c) the capacitance?

ANSWER:

Solution 1E

The relation between potential difference and the electric field between the plates is given by .

Given in the question, electric field

Distance between the plates

(a) Therefore, the potential difference

So, the potential difference is

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