Solution Found!
Answer: The plates of a parallel-plate capacitor are 2.50
Chapter 24, Problem 1E(choose chapter or problem)
Problem 1E
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00 X 106 V/m. What is (a) the potential difference between the plates; (b) the area of each plate; (c) the capacitance?
Questions & Answers
QUESTION:
Problem 1E
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00 X 106 V/m. What is (a) the potential difference between the plates; (b) the area of each plate; (c) the capacitance?
ANSWER:
Solution 1E
The relation between potential difference and the electric field between the plates is given by .
Given in the question, electric field
Distance between the plates
(a) Therefore, the potential difference
So, the potential difference is