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Solved: A potential difference Vab = 48.0 V is applied
Chapter 24, Problem 68P(choose chapter or problem)
Problem 68P
A potential difference \(V_{a b}=48.0\) V is applied across the capacitor network of Fig. E24.17. If \(C_{1}=C_{2}=4.00 \mu \mathrm{F}\)F and \(C_{4}=8.00 \mu\)F, what must the capacitance \(C_{3}\) be if the network is to store \(2.90 \times 10^{-3}\) J of electrical energy?
Equation Transcription:
Text Transcription:
V_ab=48.0
C_1=C_2=4.00 uF
C_3
2.90x10^-3
Questions & Answers
QUESTION:
Problem 68P
A potential difference \(V_{a b}=48.0\) V is applied across the capacitor network of Fig. E24.17. If \(C_{1}=C_{2}=4.00 \mu \mathrm{F}\)F and \(C_{4}=8.00 \mu\)F, what must the capacitance \(C_{3}\) be if the network is to store \(2.90 \times 10^{-3}\) J of electrical energy?
Equation Transcription:
Text Transcription:
V_ab=48.0
C_1=C_2=4.00 uF
C_3
2.90x10^-3
ANSWER:
Solution 68P
Step 1 of 6:
The capacitance of the capacitors in the given below circuit are ,
and the potential difference applied across the given capacitor network is
. The electrical energy stored in the capacitor is
.
Here we need to find the capacitance of the capacitor , by calculating the effective capacitance using electrical energy of capacitor equation and equating it with the equivalent capacitance equation of series and parallel combination capacitors to get the unknown capacitance.