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Solved: A 3.00-m length of copper wire at 20° C has a
Chapter 25, Problem 59P(choose chapter or problem)
A 3.00-m length of copper wire at \(20^{\circ} \mathrm{C}\) has a 1.20-mlong section with diameter 1.60 mm and a 1.80-m-long section with diameter 0.80 mm. There is a current of 2.5 mA in the 1.60- mm-diameter section. (a) What is the current in the 0.80-mmdiameter section? (b) What is the magnitude of \(\vec{E}\) in the 1.60-mm-diameter section? (c) What is the magnitude of \(\vec{E}\) in the 0.80-mm-diameter section? (d) What is the potential difference between the ends of the 3.00-m length of wire?
Equation Transcription:
Text Transcription:
20degC
Vector E
Vector E
Questions & Answers
QUESTION:
A 3.00-m length of copper wire at \(20^{\circ} \mathrm{C}\) has a 1.20-mlong section with diameter 1.60 mm and a 1.80-m-long section with diameter 0.80 mm. There is a current of 2.5 mA in the 1.60- mm-diameter section. (a) What is the current in the 0.80-mmdiameter section? (b) What is the magnitude of \(\vec{E}\) in the 1.60-mm-diameter section? (c) What is the magnitude of \(\vec{E}\) in the 0.80-mm-diameter section? (d) What is the potential difference between the ends of the 3.00-m length of wire?
Equation Transcription:
Text Transcription:
20degC
Vector E
Vector E
ANSWER:
Solution 59P
Step 1 of 13:
In the given problem, a L= 3m length of copper wire with resistivity has two sections. One of the section with length
=1.2 m with diameter
=1.6mm has current
=2.5 mA and the other section with
=1.8 m with diameter
=0.8 mm has current
.
In part(a) we need to calculate the current through diameter section =0.8 mm. Whereas in part (b) and (c) we have to calculate the electric fields in both the sections, that is
and
. In part (d) we have to estimate the potential difference across the given composite wire of length L=3m.