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Get Full Access to University Physics - 13 Edition - Chapter 5 - Problem 77p
Get Full Access to University Physics - 13 Edition - Chapter 5 - Problem 77p

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# CP CALC You are standing on a bathroom scale in an ISBN: 9780321675460 31

## Solution for problem 77P Chapter 5

University Physics | 13th Edition

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Problem 77P

CP CALC ?You are standing on a bathroom scale in an elevator in a tall building. Your mass is 64 kg. The elevator starts from rest and travels upward with a speed that varies with time according to v(t) = (3.0 m/s2)t + (0.20 m/s3)t2. When t = 4.0 s, what is the reading on the bathroom scale?

Step-by-Step Solution:

Solution 77P Step 1: Your mass is 64 kg. The elevator starts accelerating upwards. The velocity as a function of time is given as, 2 v(t) = 3t + 0.20 t ----------------(1) As we know that, acceleration is the time derivative of velocity, so let’s find it. dv d 2 a = dt = dt(3t + 0.20 t ) = 3 + (0.20 × 2) t = 3 + 0.40t St time t = 4 s, the acceleration will be, a = 3 + 0.40 × 4 = 4.6 m/s .2

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##### ISBN: 9780321675460

The full step-by-step solution to problem: 77P from chapter: 5 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: Scale, bathroom, elevator, according, building. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 77P from 5 chapter was answered, more than 505 students have viewed the full step-by-step answer. The answer to “CP CALC ?You are standing on a bathroom scale in an elevator in a tall building. Your mass is 64 kg. The elevator starts from rest and travels upward with a speed that varies with time according to v(t) = (3.0 m/s2)t + (0.20 m/s3)t2. When t = 4.0 s, what is the reading on the bathroom scale?” is broken down into a number of easy to follow steps, and 58 words.

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