A Volume Gauge. A tank containing a liquid has turns of

QUESTION:

A Volume Gauge. A tank containing a liquid has turns of wire wrapped around it, causing it to act like an inductor. The liquid content of the tank can be measured by using its inductance to determine the height of the liquid in the tank. The inductance of the tank changes from a value of \(L_{0}\) corresponding to a relative permeability of 1 when the tank is empty to a value of \(L_{f}\) corresponding to a relative permeability of \(K_{m}\) (the relative permeability of the liquid) when the tank is full. The appropriate electronic circuitry can determine the inductance to five significant figures and thus the effective relative permeability of the combined air and liquid within the rectangular cavity of the tank. The four sides of the tank each have width W and height D (Fig. P30.77). The height of the liquid in the tank is d. You can ignore any fringing effects and assume that the relative permeability of the material of which the tank is made can be ignored. (a) Derive an expression for d as a function of L, the inductance corresponding to a certain fluid height \(L_{0}\), \(L_{f}\), and D. (b) What is the inductance (to five significant figures) for a tank \(\frac{1}{4}\) full, \(\frac{1}{2}\) full, \(\frac{3}{4}\) full, and completely full if the tank contains liquid oxygen? Take \(L_{0}=0.63000\) H. The magnetic susceptibility of liquid oxygen is \(X_{m}=1.52 \times 10^{-3}\). (c) Repeat part (b) for mercury. The magnetic susceptibility of mercury is given in Table 28.1. (d) For which material is this volume gauge more practical?

Equation Transcription:

Text Transcription:

L_0

L_f

K_m

L_0

L_f

1/4

1/2

3/4

L_0=0.63000

X_m=1.5210-3