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A woman bounces on a trampoline, going a little higher

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 8DQ Chapter 7

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 8DQ

A woman bounces on a trampoline, going a little higher with each bounce. Explain how she increases the total mechanical energy.

Step-by-Step Solution:

Solution 8DQ Step 1: For the first bounce, she uses her muscular force upward and she will go up for a short distance, h. Suppose, the mass of the woman as “m”. We know that the acceleration due to gravity is “g”. The potential energy of the lady at a height “h” is, U = mgh Consider. for the initial jump, the energy spent by the muscles as “M” After the first jump, the energy acquired by the woman will be, E second jump + U This is represented as E second jumpause, this energy is used for the second jump. So, the height of jump will increase and it will be h + h. The potential energy acquired at maximum point will be, U ’ = mg ( h + h) The energy acquired for the 3rd jump will be, E 3rd M + U’

Step 2 of 2

Chapter 7, Problem 8DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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A woman bounces on a trampoline, going a little higher