Tarzan and Jane. Tarzan, in one tree, sights Jane in another tree. He grabs the end of a vine with length 20 m that makes an angle of 45o with the vertical, steps off his tree limb, and swings down and then up to Jane’s open arms. When he arrives, his vine makes an angle of 30o with the vertical. Determine whether he gives her a tender embrace or knocks her off her limb by calculating Tarzan’s speed just before he reaches Jane. Ignore air resistance and the mass of the vine.

Solution 12E Step 1 of 3: o Tarzan from one tree limb at the point A steps off the tree using L=20m vine with 45 o from vertical plane and arrives at another tree at point B by making an angle 30 from vertical plane. We need to calculate at what speed tarzan arrives at point B to knock off jane. The pictorial representation of given problem is given below, Step 2 of 3: Vertical height (initial) = L - LcosA = L(1-cos 45) = 20 x 0.29 = 5.8m Vertical height (final) = L(1-cos 30) = 20 x 0.13 = 2.6m Loss in vertical height, h= 5.8 - 2.6 = 3.2m Since here Loss in Potential energy will be equal to the Gain in Kinetic energy and Let the final velocity of the Tarzan is v m/s That is, PE = KE mgh = mv1 2 2 gh = v 2 2