Answer: The electric field at one face of a parallelepiped

Chapter 22, Problem 37P

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QUESTION:

The electric field \(\overline{E_{1}}\) at one face of a parallelepiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field \(\overline{E_{2}}\) is also uniform over the entire face and is directed into that face (Fig. P22.37). The two faces in question are inclined at  from the horizontal, while \(\overline{E_{1}}\) and \(\overline{E_{2}}\) are both horizontal; \(\overline{E_{1}}\) has a magnitude of \(2.50 \times 10^{4} \mathrm{~N} / \mathrm{C}\), and \(\overline{E_{2}}\) has a magnitude of \(7.00 \times 10^{4} N / C\). (a) Assuming that no other electric field lines cross the surfaces of the parallelepiped, determine the net charge contained within. (b) Is the electric field produced only by the charges within the parallelepiped, or is the field also due to charges outside the parallelepiped? How can you tell?

Equation transcription:

Text transcription:

overline{E_{1}}

overline{E_{2}}

2.50 \times 10^{4{~N}{C}

7.00 \times 10^{4} N / C

Questions & Answers

QUESTION:

The electric field \(\overline{E_{1}}\) at one face of a parallelepiped is uniform over the entire face and is directed out of the face. At the opposite face, the electric field \(\overline{E_{2}}\) is also uniform over the entire face and is directed into that face (Fig. P22.37). The two faces in question are inclined at  from the horizontal, while \(\overline{E_{1}}\) and \(\overline{E_{2}}\) are both horizontal; \(\overline{E_{1}}\) has a magnitude of \(2.50 \times 10^{4} \mathrm{~N} / \mathrm{C}\), and \(\overline{E_{2}}\) has a magnitude of \(7.00 \times 10^{4} N / C\). (a) Assuming that no other electric field lines cross the surfaces of the parallelepiped, determine the net charge contained within. (b) Is the electric field produced only by the charges within the parallelepiped, or is the field also due to charges outside the parallelepiped? How can you tell?

Equation transcription:

Text transcription:

overline{E_{1}}

overline{E_{2}}

2.50 \times 10^{4{~N}{C}

7.00 \times 10^{4} N / C

ANSWER:

Solution 37P

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