Solution Found!
Solved: In Fig, C1 = 6.00 µF, C2 = 3.00 µF, and C3 = 5.00
Chapter 24, Problem 20E(choose chapter or problem)
In Fig. E24.20, \(C_{1}=6.00 \mu F, C_{2}=3.00 \mu F\), and \(C_{3}=5.00 \mu F\). The capacitor network is connected to an applied potential \(V_{a b}\). After the charges on the capacitors have reached their final values, the charge on \(C_{2}\) is \(40.0 \mu C\). (a) What are the charges on capacitors \(C_{1}\) and \(C_{3}\)? (b) What is the applied voltage \(V_{a b}\)?
Equation transcription:
Text transcription:
C{1}=6.00 \mu F, C{2}=3.00 \mu F
C{3}=5.00 \mu F
C{2}
40.0 \mu C
C{1}
C{3}
V{a b}
Questions & Answers
QUESTION:
In Fig. E24.20, \(C_{1}=6.00 \mu F, C_{2}=3.00 \mu F\), and \(C_{3}=5.00 \mu F\). The capacitor network is connected to an applied potential \(V_{a b}\). After the charges on the capacitors have reached their final values, the charge on \(C_{2}\) is \(40.0 \mu C\). (a) What are the charges on capacitors \(C_{1}\) and \(C_{3}\)? (b) What is the applied voltage \(V_{a b}\)?
Equation transcription:
Text transcription:
C{1}=6.00 \mu F, C{2}=3.00 \mu F
C{3}=5.00 \mu F
C{2}
40.0 \mu C
C{1}
C{3}
V{a b}
ANSWER:Solution 20E
Step 1
Identify: This problem is related to the resultant capacitance of the capacitors connected in series and parallel. In parallel combination the charge deposited on the capacitors is different for the different capacitors and the potential difference is same for all the capacitors.