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A marble moves along the x -axis. The potential-energy

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 38E Chapter 7

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 38E

A marble moves along the x -axis. The potential-energy function is shown in Fig. E7.36. (a) At which of the labeled x-coordinates is the force on the marble zero? (b) Which of the labeled x-coordinates is a position of stable equilibrium? (c) Which of the labeled x-coordinates is a position of unstable equilibrium?

Step-by-Step Solution:

Solution 38E Problem (a) Step 1: To find the coordinates(x) where force on the marble is zero Consider force on the marble is F to be zero, the slope of potential energy versus x must x be zero. Points b and d are having zero slope value on the graph. Therefore value of force is zero where x coordinates are (b) and (d). Problem (b) Step 1: To find the coordinates(x) where marble is at stable equilibrium For a particle to be at stable equilibrium it must possess minimum potential energy. Our diagram, the marble has minimum potential energy at point (b) at x coordinate. Problem (c) Step 1: To find the coordinates(x) where marble is at unstable equilibrium Point (d) at x coordinate is the position of unstable equilibrium, because the marble at point (d) has maximum potential energy.

Step 2 of 1

Chapter 7, Problem 38E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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A marble moves along the x -axis. The potential-energy