In Fig. 8.22b, the kinetic energy of the Ping-Pong ball is larger after its interaction with the bowling ball than before. From where does the extra energy come? Describe the event in terms of conservation of energy.
Solution 13DQ Step 1 of 3: Before collision the the bowling ball of mass M was moving with speed v and the ping b1 pong ball is at rest with velocity zero v = 0 as shown in the figure below, p1 The energy of the system before collision, E 1 Kinetic energy of bowling ball + potential energy of ping pong ball E1= mv2 2 + PE ………….1 b1